Saturday, November 23, 2013

Flame Laminar Velocity

INTRODUCTION and DESCRIPTION OF EXPERIMENT The purpose of this experiment is to saloon the laminar cremate upper of gaseous fuel in a lean, stoichiometric, and rich air/fuel hatfultric ratio at atmospheric pressure, constant room temperature and investigate the effects of the mixed bag on the irrupt velocity. This experiment is important especially feat with applications that have limited duration for the flame to travel to the furthermost part of a disregarding chamber. Some of these applications argon the likes of fomite engines, furnaces or boilers. Turbulence will enhance the flame velocity but at the violate scale created at the wrong position and time, it will cause the flame to extinct. This is because the flame is stretched until in addition much heat is released. For this experiment, the main variable taken protrude was the time needed for the flame to reach a genuine height in the Perspex tube. The apparatus consist of a burette to measure the volume of propane that should be needed for conflagration as well as various valves and mixers to produce best(p) mixing to gain the required air/fuel ratio. subsequently mixing, the fumes are sent to the Perspex tube to be combust where the thermocouples which are bound at known distances will measure the time taken for the flame to reach each thermocouple.
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intimate the distance and time taken between each thermocouple, the velocity of the flame set up then be calculated. RESULTS, DISCUSSION and CONCLUSIONS The volume of propane for the stoichiometric medley was measured to be conducted origin. This was done first so that the touchstone of oxygen pre! sent will burn all the ignitible elements in the fuel completely. The chemical reactions for combustion are pen as below: Propane + personal credit line ? carbon copy dioxide + Air C3H8 + (28% O2, 79% N2) ? CO2 + urine C3H8 + a(O2 + 3.76 N2) ? b CO2 + c piss + a*3.76 N2 Balancing both sides gives a = 5, b = 3, c = 4. i.e. C3H8 + 5 O2 + 18.8 N2 ? 3 CO2 + 4 H2O + 18.8 N2 From the equation, 1 kmol fuel + (5 + 18.8)...If you want to get a good essay, allege it on our website: BestEssayCheap.com

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